A body of mass 10 kg is acted upon by two forces each of magnitude 10 N making an angle of 60° with each other. Find the net acceleration of the body.

Question

A body of mass 10 kg is acted upon by two forces each of magnitude 10 N making an angle of 60° with each other. Find the net acceleration of the body. (A)  2√3m/s2 (B)  √3m/s2 (C)  3√3m/s2 (D)  4√3m/s2

Tardigrade Admin · Accepted Answer

F text net =√F12+F22+2 F1 F2 cos θ =√(10)2+(10)2+2 × 10 × 10 × cos 60° =√100+100+100=10 √3 Mass of the body =10 kg ∴ Acceleration =( text force / text mass ) =(10 √3/10)=√3 m / s 2

Q. A body of mass $10 k g$ is acted upon by two forces each of magnitude $10 N$ making an angle of $6 0^{\circ}$ with each other. Find the net acceleration of the body.

$23 m / s^{2}$

$3 m / s^{2}$

$33 m / s^{2}$

$43 m / s^{2}$

$F_{net} = F_{1}^{2} + F_{2}^{2} + 2 F_{1} F_{2} cos θ$
$= (10)^{2} + (10)^{2} + 2 \times 10 \times 10 \times cos 6 0^{\circ}$
$= 100 + 100 + 100 = 103$
Mass of the body $= 10 k g$
$∴$ Acceleration $= \frac{force}{mass}$
$= \frac{10 3}{10} = 3 m / s^{2}$

Q. A body of mass 10kg is acted upon by two forces each of magnitude 10N making an angle of 60∘ with each other. Find the net acceleration of the body.

23​m/s2

3​m/s2

33​m/s2

43​m/s2