A body of mass 1 kg is projected from ground at an angle 30° with horizontal on a level ground at a speed 50 m / s. The magnitude of change in momentum of the body during its flight is (g=10 m / s 2. )

Question

A body of mass 1 kg is projected from ground at an angle 30° with horizontal on a level ground at a speed 50 m / s. The magnitude of change in momentum of the body during its flight is (g=10 m / s 2. ) (A) 50 kg ms -1 (B) 100 kg ms -1 (C) 25 kg ms -1 (D) Zero

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/87efeae1f1fd453df6cc4fcde56a8374-.png" /> ⇒ The change in momentum =-2 m u sin θ hatj |Δ vecp|=2 m u sin θ =2 × 1 × 50 × sin 30° |Δ vecp|=50 Kg ms -1

Q. A body of mass $1 k g$ is projected from ground at an angle $3 0^{\circ}$ with horizontal on a level ground at a speed $50 m / s$ . The magnitude of change in momentum of the body during its flight is $(g = 10 m / s^{2}$ )

$50 k g m s^{- 1}$

$100 k g m s^{- 1}$

$25 k g m s^{- 1}$

Zero

$\Rightarrow$ The change in momentum $= - 2 m u sin θ \hat{j}$
$∣Δ p ∣ = 2 m u sin θ$
$= 2 \times 1 \times 50 \times sin 3 0^{\circ}$
$∣Δ p ∣ = 50 K g m s^{- 1}$

Q. A body of mass 1kg is projected from ground at an angle 30∘ with horizontal on a level ground at a speed 50m/s. The magnitude of change in momentum of the body during its flight is (g=10m/s2 )

50kgms−1

100kgms−1

25kgms−1