A body of length 1 m having cross-sectional area 0.75 m2 has heat flow through it at the rate of 6000 J/s. Then find the temperature difference if K = 200Jm-2 K-1.

Question

A body of length 1 m having cross-sectional area 0.75 m2 has heat flow through it at the rate of 6000 J/s. Then find the temperature difference if K = 200Jm-2 K-1. (A) 20° C (B) 40° C (C) 80° C (D) 100° C

Tardigrade Admin · Accepted Answer

The rate of heat flow, (Q/t)=(KAΔθ/I) ⇒ 6000=(200×0.75×Δθ/1) Δθ=(6000×1/200×0.75) = 40° C

Q. A body of length 1 m having cross-sectional area $0.75 m^{2}$ has heat flow through it at the rate of 6000 J/s. Then find the temperature difference if $K = 200 J m^{- 2} K^{- 1}$ .

$2 0^{\circ} C$

$4 0^{\circ} C$

$8 0^{\circ} C$

$10 0^{\circ} C$

The rate of heat flow, $\frac{Q}{t} = \frac{K A Δ θ}{I}$ $\Rightarrow 6000 = \frac{200 \times 0.75 \times Δ θ}{1}$ $Δ θ = \frac{6000 \times 1}{200 \times 0.75} = 4 0^{\circ} C$

Q. A body of length 1 m having cross-sectional area 0.75m2 has heat flow through it at the rate of 6000 J/s. Then find the temperature difference if K=200Jm−2K−1.

20∘C

40∘C

80∘C

100∘C