A body moving with uniform acceleration has a velocity of -9 cm / s when its x co-ordinate is 3.00 cm. If its x coordinate 3 s later is -6 cm, what is the magnitude of its acceleration (. in .cm / s 2) ?

Question

A body moving with uniform acceleration has a velocity of -9 cm / s when its x co-ordinate is 3.00 cm. If its x coordinate 3 s later is -6 cm, what is the magnitude of its acceleration (. in .cm / s 2) ? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

u=-9 cm / s s=-6-3=-9 cm t=3 s s=u t+(1/2) a t2 -9=-9 × 3+(1/2)+a × 32 a=4 cm / s 2

Q. A body moving with uniform acceleration has a velocity of $- 9 c m / s$ when its $x$ co-ordinate is $3.00 c m$ . If its $x$ coordinate $3 s$ later is $- 6 c m$ , what is the magnitude of its acceleration $($ in $c m / s^{2})$ ?

$u = - 9 c m / s$
$s = - 6 - 3 = - 9 c m$
$t = 3 s$
$s = u t + \frac{1}{2} a t^{2}$
$- 9 = - 9 \times 3 + \frac{1}{2} + a \times 3^{2}$
$a = 4 c m / s^{2}$

Q. A body moving with uniform acceleration has a velocity of −9cm/s when its x co-ordinate is 3.00cm. If its x coordinate 3s later is −6cm, what is the magnitude of its acceleration ( in cm/s2) ?

u=−9cm/s s=−6−3=−9cm t=3s s=ut+21​at2 −9=−9×3+21​+a×32 a=4cm/s2

Q. A body moving with uniform acceleration has a velocity of $- 9 c m / s$ when its $x$ co-ordinate is $3.00 c m$ . If its $x$ coordinate $3 s$ later is $- 6 c m$ , what is the magnitude of its acceleration $($ in $c m / s^{2})$ ?

$u = - 9 c m / s$
$s = - 6 - 3 = - 9 c m$
$t = 3 s$
$s = u t + \frac{1}{2} a t^{2}$
$- 9 = - 9 \times 3 + \frac{1}{2} + a \times 3^{2}$
$a = 4 c m / s^{2}$