Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A body moving with uniform acceleration describes 12 m in the third second of its motion and 20 m in the 5th second. Find the velocity after 10 th second.
Q. A body moving with uniform acceleration describes 12 m in the third second of its motion and 20 m in the 5th second. Find the velocity after 10 th second.
2519
227
Jharkhand CECE
Jharkhand CECE 2011
Report Error
A
40 m/s
B
42 m/s
C
52 m/s
D
4m/s
Solution:
S
n
=
u
+
2
a
(
2
n
−
1
)
12
=
u
+
2
a
(
2
×
3
−
1
)
..(i)
and
20
=
u
+
2
a
(
2
×
5
−
1
)
..(ii)
Subtract Eq. (i) from Eq. (ii)
8
=
2
a
(
9
−
5
)
=
2
a
⇒
a
=
4
m
/
s
2
From Eq. (i)
12
=
u
+
2
4
×
5
u
=
2
m
/
s
Velocity
v
=
u
+
a
t
=
2
+
4
×
10
=
42
m
/
s