Q.
A body moving along a straight line with a uniform acceleration covers 20cm in one second and 30cm in very next second. The body has an acceleration of
Let the initial velocity be u and acceleration be a.
Case 1:
Distance covered S=20m
Time taken t=1s
Using S=ut+21at2
Or 20=u(1)+21a(1)2 ⟹20=u+2a
We get u=20−2a
Case 2 :
Total distance covered S=20+30=50m
Total time taken t=1+1=2s
So, 50=u(2)+21a(2)2
or 50=2u+2a
Or 50=2(20−2a)+2a
Or 50=40−a+2a ⟹a=10m/s2