A body moves with speed V1 for distance L and then with speed V2 for distance 2L . The average speed for the motion is

Question

A body moves with speed V1 for distance L and then with speed V2 for distance 2L . The average speed for the motion is (A) (V1 + V2/2) (B) (3 V1 V2/V1 + 2 V2) (C) (3 V1 V2/2 V1 + V2) (D) (3 V1 V2/V1 + V2)

Tardigrade Admin · Accepted Answer

Average speed =( textTotal distance/ textTotal time) =(3 L/(L)V1 + (2 L)V2 =(3 V1 V2/V2 + 2 V1)

Q. A body moves with speed $V_{1}$ for distance $L$ and then with speed $V_{2}$ for distance $2 L$ . The average speed for the motion is

$\frac{V _{1} + V _{2}}{2}$

$\frac{3 V _{1} V _{2}}{V _{1} + 2 V _{2}}$

$\frac{3 V _{1} V _{2}}{2 V _{1} + V _{2}}$

$\frac{3 V _{1} V _{2}}{V _{1} + V _{2}}$

Average speed $= \frac{Total distance}{Total time}$
$= \frac{3 L}{\frac{L}{V _{1}} + \frac{2 L}{V _{2}}}$
$= \frac{3 V _{1} V _{2}}{V _{2} + 2 V _{1}}$

Q. A body moves with speed V1​ for distance L and then with speed V2​ for distance 2L . The average speed for the motion is

2V1​+V2​​

V1​+2V2​3V1​V2​​

2V1​+V2​3V1​V2​​

V1​+V2​3V1​V2​​