Q.
A body moves a distance of 10m along a straight line under a action of 5N force. If work done is 25J, then angle between the force and direction of motion of the body will be
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AIPMTAIPMT 1997Work, Energy and Power
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Solution:
Distance (s)=10m;
Force (F)=5N and work done (W)=25J.
Work done (W)=Fscosθ=25 ∴25=5×10cosθ=50cosθ
or cosθ=25/50=0.5
or θ=60∘.