Question

A body is thrown vertically upward with velocity $u$. The ratio of times at which it is at particular height $h$ is $1:2$. What is the maximum height reached by the body above point of projection?

• A. (9/4)h
• B. (4/3)h
• C. (9/8)h
• D. none of these

Answer 1

Answer: (C)

$H=\frac{u^2}{2g}...\left(i\right)$

$\frac{t_1}{t_2}=\frac{1}{2}$

$\Rightarrow 2t_1=t_2...\left(ii\right)$

$u=\frac{1}{2}g\left(t_1+t_2\right)...\left(iii\right)$

$h=\frac{1}{2}g{t}_1{t}_2...\left(iv\right)$

From $\left(ii\right),\left(iii\right)$ and $\left(iv\right)$

$u^2=\frac{9gh}{4}$

Put $u^2$ in equation $\left(i\right):H=\frac{9}{8}h$