A body is projected, making an acute angle with the horizontal. If angle between velocity vecv and acceleration vecg is θ then

Question

A body is projected, making an acute angle with the horizontal. If angle between velocity vecv and acceleration vecg is θ then (A) θ = 90° (B) θ = 0° (C) 90°< θ < 0° (D) 0°< θ < 180°

Tardigrade Admin · Accepted Answer

Here velocity is acting upwards when projectile is going upwards and acceleration is downwards. The angle q between vecv and veca is more than 0° and less than 180°.

Q. A body is projected, making an acute angle with the horizontal. If angle between velocity $v$ and acceleration $g$ is $θ$ then

$θ = 9 0^{\circ}$

$θ = 0^{\circ}$

$9 0^{\circ} < θ < 0^{\circ}$

$0^{\circ} < θ < 18 0^{\circ}$

Here velocity is acting upwards when projectile is going upwards and acceleration is downwards. The angle $q$ between $v$ and $a$ is more than $0^{\circ}$ and less than $18 0^{\circ}$ .

Q. A body is projected, making an acute angle with the horizontal. If angle between velocity v and acceleration g​ is θ then

θ=90∘

θ=0∘

90∘<θ<0∘

0∘<θ<180∘