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Physics
A body is projected, making an acute angle with the horizontal. If angle between velocity vecv and acceleration vecg is θ then
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Q. A body is projected, making an acute angle with the horizontal. If angle between velocity $\vec{v}$ and acceleration $\vec{g}$ is $\theta$ then
BITSAT
BITSAT 2013
A
$\theta = 90^{\circ}$
10%
B
$\theta = 0^{\circ}$
8%
C
$90^{\circ}< \theta < 0^{\circ}$
21%
D
$0^{\circ}< \theta < 180^{\circ}$
60%
Solution:
Here velocity is acting upwards when projectile is going upwards and acceleration is downwards. The angle $q$ between $\vec{v}$ and $\vec{a}$ is more than $0^{\circ}$ and less than $180^{\circ}$.