A body is projected from the ground with a velocity vecv = (3 hati+10 hatj)ms-1 The maximum height attained and the range of the body respectively are (given g = 10 ms-2)

Question

A body is projected from the ground with a velocity vecv = (3 hati+10 hatj)ms-1 The maximum height attained and the range of the body respectively are (given g = 10 ms-2) (A) 5 m and 6 m (B) 3 m and 10 m (C) 6 m and 5 m (D) 3 m and 5 m

Tardigrade Admin · Accepted Answer

Given, v =(3 hat i +10 hat j ) m / s ⇒ vx=3 text and vy=10 ∴ Maximum height attained, H=(vy2/2 g) =(10 × 10/2 × 10)=5 m Range =vx × T=vx × (2 vy/g)=(3 × 2 × 10/10)=6 m

Q. A body is projected from the ground with a velocity $v = (3 \hat{i} + 10 \hat{j}) m s^{- 1}$ The maximum height attained and the range of the body respectively are (given g $= 10 m s^{- 2}$ )

5 m and 6 m

3 m and 10 m

6 m and 5 m

3 m and 5 m

Given, $v = (3 \hat{i} + 10 \hat{j}) m / s$
$\Rightarrow v_{x} = 3 and v_{y} = 10$
$∴$ Maximum height attained, $H = \frac{v _{y}^{2}}{2 g}$
$= \frac{10 \times 10}{2 \times 10} = 5 m$
Range $= v_{x} \times T = v_{x} \times \frac{2 v _{y}}{g} = \frac{3 \times 2 \times 10}{10} = 6 m$

Q. A body is projected from the ground with a velocity v=(3i^+10j^​)ms−1 The maximum height attained and the range of the body respectively are (given g =10ms−2)