A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms -1. The maximum height reached by the body during its motion is m .(. use g =10 ms -2 )

Question

A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms -1. The maximum height reached by the body during its motion is m .(. use g =10 ms -2 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/61ce13f18872cfeb79ecc176038245ae-.png" /> v y = v x -20 √( u x -20)2+ u x 2=20 ⇒ 2 u x 2-40 u x =0 ∴ u x =20

Q. A body is projected from the ground at an angle of $4 5^{\circ}$ with the horizontal. Its velocity after $2 s$ is $20 m s^{- 1}$ . The maximum height reached by the body during its motion is ______ $m . ($ use $g = 10 m s^{- 2}$ )

$v_{y} = v_{x} - 20$
$(u_{x} - 20)^{2} + u_{x}^{2} = 20$
$\Rightarrow 2 u_{x}^{2} - 40 u_{x} = 0$
$∴ u_{x} = 20$

Q. A body is projected from the ground at an angle of 45∘ with the horizontal. Its velocity after 2s is 20ms−1. The maximum height reached by the body during its motion is ______ m.( use g=10ms−2 )

vy​=vx​−20 (ux​−20)2+ux2​​=20 ⇒2ux2​−40ux​=0 ∴ux​=20

Q. A body is projected from the ground at an angle of $4 5^{\circ}$ with the horizontal. Its velocity after $2 s$ is $20 m s^{- 1}$ . The maximum height reached by the body during its motion is ______ $m . ($ use $g = 10 m s^{- 2}$ )

$v_{y} = v_{x} - 20$
$(u_{x} - 20)^{2} + u_{x}^{2} = 20$
$\Rightarrow 2 u_{x}^{2} - 40 u_{x} = 0$
$∴ u_{x} = 20$