A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is:

Question

A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is: (A) n (B) 2 n (C) 3 n (D) 4 n

Tardigrade Admin · Accepted Answer

Potential energy of a particle executing SHM is given by U =(1/2) m ω2 x 2 So, if the frequency of oscilation is n, then frequency of its potential energy will be 2 n.

Q. A body is executing simple harmonic motion with frequency $^{'} n^{'}$ , the frequency of its potential energy is:

n

2 n

3 n

4 n

Potential energy of a particle executing SHM is given by
$U = \frac{1}{2} m ω^{2} x^{2}$
So, if the frequency of oscilation is $n$ ,
then frequency of its potential energy will be $2 n$ .

Q. A body is executing simple harmonic motion with frequency ′n′, the frequency of its potential energy is:

n

2 n

3 n

4 n

Potential energy of a particle executing SHM is given by U=21​mω2x2 So, if the frequency of oscilation is n, then frequency of its potential energy will be 2n.

Q. A body is executing simple harmonic motion with frequency $^{'} n^{'}$ , the frequency of its potential energy is:

Potential energy of a particle executing SHM is given by
$U = \frac{1}{2} m ω^{2} x^{2}$
So, if the frequency of oscilation is $n$ ,
then frequency of its potential energy will be $2 n$ .