A body is dropped from a certain height h(h is very large) and second body is thrown downward with velocity of 5 m / s simultaneouly. What will be difference in heights of the two bodies after 3 s ?

Question

A body is dropped from a certain height h(h is very large) and second body is thrown downward with velocity of 5 m / s simultaneouly. What will be difference in heights of the two bodies after 3 s ? (A) 5 m (B) 10 m (C) 15 m (D) 20 m

Tardigrade Admin · Accepted Answer

u text rel =u1-u2=0-(-5)=5 ms -1 t=3 s a rel = a 1-a2=-g-(-g)=0 ms -2 s rel =u rel t+(1/2) a rel t2 ⇒ s rel =5 × 3=15 m (∵ a rel =0) So, S text rel =15 m

Q. A body is dropped from a certain height $h (h$ is very large) and second body is thrown downward with velocity of $5 m / s$ simultaneouly. What will be difference in heights of the two bodies after $3 s$ ?

5 m

10 m

15 m

20 m

$u_{rel} = u_{1} - u_{2} = 0 - (- 5) = 5 m s^{- 1}$
$t = 3 s$
$a_{re l} = a_{1} - a_{2} = - g - (- g) = 0 m s^{- 2}$
$s_{re l} = u_{re l} t + \frac{1}{2} a_{re l} t^{2}$
$\Rightarrow s_{re l} = 5 \times 3 = 15 m (∵ a_{re l} = 0)$
So, $S_{rel} = 15 m$

Q. A body is dropped from a certain height h(h is very large) and second body is thrown downward with velocity of 5m/s simultaneouly. What will be difference in heights of the two bodies after 3s ?

5 m

10 m

15 m

20 m

urel ​=u1​−u2​=0−(−5)=5ms−1 t=3s arel​=a1​−a2​=−g−(−g)=0ms−2 srel​=urel​t+21​arel​t2 ⇒srel​=5×3=15m(∵arel​=0) So, Srel ​=15m

Q. A body is dropped from a certain height $h (h$ is very large) and second body is thrown downward with velocity of $5 m / s$ simultaneouly. What will be difference in heights of the two bodies after $3 s$ ?

$u_{rel} = u_{1} - u_{2} = 0 - (- 5) = 5 m s^{- 1}$
$t = 3 s$
$a_{re l} = a_{1} - a_{2} = - g - (- g) = 0 m s^{- 2}$
$s_{re l} = u_{re l} t + \frac{1}{2} a_{re l} t^{2}$
$\Rightarrow s_{re l} = 5 \times 3 = 15 m (∵ a_{re l} = 0)$
So, $S_{rel} = 15 m$