A body has a weight 90 kg on the earths surface, the mass of the moon is 1/9 that of the earths mass and its radius is 1/2 that of the earths radius. On the moon the weight of the body is:

Question

A body has a weight 90 kg on the earths surface, the mass of the moon is 1/9 that of the earths mass and its radius is 1/2 that of the earths radius. On the moon the weight of the body is: (A) 45 kg (B) 202.5 kg (C) 90 kg (D) 40 kg

Tardigrade Admin · Accepted Answer

Acceleration due to gravity on earth is given by (m upsilon 2/r)=4mg ∴ Hence upsilon 2=4rg upsilon =√4rg or upsilon =√4× 2.5× 9.8 upsilon =√98 m/s Weight of body on moon text20 text g = text 2× text10- text2 text kg, =(360× 5/18)=100m/s

Q. A body has a weight 90 kg on the earths surface, the mass of the moon is 1/9 that of the earths mass and its radius is 1/2 that of the earths radius. On the moon the weight of the body is:

45 kg

202.5 kg

90 kg

40 kg

Acceleration due to gravity on earth is given by $\frac{m υ ^{2}}{r} = 4 m g$ $∴$ Hence $υ^{2} = 4 r g$ $υ = 4 r g$ or $υ = 4 \times 2.5 \times 9.8$ $υ = 98 m / s$ Weight of body on moon $20 g = 2 \times 1 0^{- 2} kg,$ $= \frac{360 \times 5}{18} = 100 m / s$

Q. A body has a weight 90 kg on the earths surface, the mass of the moon is 1/9 that of the earths mass and its radius is 1/2 that of the earths radius. On the moon the weight of the body is:

45 kg

202.5 kg

90 kg

40 kg

Acceleration due to gravity on earth is given by rmυ2​=4mg ∴ Hence υ2=4rg υ=4rg​ or υ=4×2.5×9.8​ υ=98​m/s Weight of body on moon 20 g = 2×10−2 kg, =18360×5​=100m/s

Acceleration due to gravity on earth is given by $\frac{m υ ^{2}}{r} = 4 m g$ $∴$ Hence $υ^{2} = 4 r g$ $υ = 4 r g$ or $υ = 4 \times 2.5 \times 9.8$ $υ = 98 m / s$ Weight of body on moon $20 g = 2 \times 1 0^{- 2} kg,$ $= \frac{360 \times 5}{18} = 100 m / s$