Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A body executing S.H.M. along a straight line has a velocity of 3 ms -1 when it is at a distance of 4 m from its mean position and 4 ms -1 when it is at a distance of 3 m from its mean position. Its angular frequency and amplitude are
Q. A body executing S.H.M. along a straight line has a velocity of
3
m
s
−
1
when it is at a distance of
4
m
from its mean position and
4
m
s
−
1
when it is at a distance of
3
m
from its mean position. Its angular frequency and amplitude are
4264
213
Oscillations
Report Error
A
2
r
a
d
s
−
1
&5
m
B
1
r
a
d
s
−
1
&10
m
C
2
r
a
d
s
−
1
&10
m
D
1
r
a
d
s
−
1
&5
m
Solution:
v
=
ω
A
2
−
x
2
v
1
=
3
m
/
s
x
1
=
4
m
v
2
=
4
m
/
s
x
2
=
3
m
3
=
ω
A
2
−
4
2
... (i)
4
=
ω
A
2
−
3
2
... (ii)
iolving (i) and (ii), we get
A
=
5
m
and
ω
=
1
r
a
d
/
s