A body dropped from the top of a tower covers a distance 7x in the last second of its journey, where x is the distance covered in first second. How much time does it take to reach the ground?

Question

A body dropped from the top of a tower covers a distance 7x in the last second of its journey, where x is the distance covered in first second. How much time does it take to reach the ground? (A) 3s (B) 4s (C) 5s (D) 6s

Tardigrade Admin · Accepted Answer

Given, 7x=(g/2)(2n-1) and x=(1/2)g(1)2 Solving these two equations n=4s.

Q. A body dropped from the top of a tower covers a distance $7 x$ in the last second of its journey, where $x$ is the distance covered in first second. How much time does it take to reach the ground?

3s

4s

5s

6s

Given, $7 x = \frac{g}{2} (2 n - 1)$
and $x = \frac{1}{2} g (1)^{2}$
Solving these two equations
$n = 4 s .$

Q. A body dropped from the top of a tower covers a distance 7x in the last second of its journey, where x is the distance covered in first second. How much time does it take to reach the ground?

3s

4s

5s

6s

Given, 7x=2g​(2n−1) and x=21​g(1)2 Solving these two equations n=4s.

Q. A body dropped from the top of a tower covers a distance $7 x$ in the last second of its journey, where $x$ is the distance covered in first second. How much time does it take to reach the ground?

Given, $7 x = \frac{g}{2} (2 n - 1)$
and $x = \frac{1}{2} g (1)^{2}$
Solving these two equations
$n = 4 s .$