A body crosses the top most point of a vertical circle with critical speed. Its centripetal acceleration, when the string at the lowest point of circle/loop:

Question

A body crosses the top most point of a vertical circle with critical speed. Its centripetal acceleration, when the string at the lowest point of circle/loop: (A) 3 g (B) g (C) 5 g (D) 6 g

Tardigrade Admin · Accepted Answer

At the lowest position v=√g R Centripetal acceleration ac=(v2/R)=((√g R)2/R)=g

Q. A body crosses the top most point of a vertical circle with critical speed. Its centripetal acceleration, when the string at the lowest point of circle/loop:

$3 g$

$g$

$5 g$

$6 g$

At the lowest position $v = g R$
Centripetal acceleration $a_{c} = \frac{v ^{2}}{R} = \frac{( g R ) ^{2}}{R} = g$

Q. A body crosses the top most point of a vertical circle with critical speed. Its centripetal acceleration, when the string at the lowest point of circle/loop:

3g

g

5g

6g

At the lowest position v=gR​ Centripetal acceleration ac​=Rv2​=R(gR​)2​=g

$3 g$

$g$

$5 g$

$6 g$

At the lowest position $v = g R$
Centripetal acceleration $a_{c} = \frac{v ^{2}}{R} = \frac{( g R ) ^{2}}{R} = g$