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Q.
A body crosses the top most point of a vertical circle with critical speed. Its centripetal acceleration, when the string at the lowest point of circle/loop:
Work, Energy and Power
Solution:
At the lowest position $v=\sqrt{g R}$
Centripetal acceleration $a_{c}=\frac{v^{2}}{R}=\frac{(\sqrt{g R})^{2}}{R}=g$