The distance covered in nth second is Sn=u+21(2n−1)a
where u is initial velocity & a is acceleration then 26=u+219a .....(1) 28=u+221a ....(2) 30=u+223a .....(3) 32=u+225a ......(4)
From eq. (1) & (2) we get u = 7m/sec,a=2m/sec2 ∴ The body starts with initial velocity u = 7 m/sec
and moves with uniform acceleration a=2m/sec2