A block of pure silicon at 300 K has a length of 10 cm and an area of 1.0 cm2. A battery of emf 2 V is connected across it. The mobility of electrons is 0.14 m2 V-1 s-1 and their number density is 1.5 × 1016 m-3. The electron current is

Question

A block of pure silicon at 300 K has a length of 10 cm and an area of 1.0 cm2. A battery of emf 2 V is connected across it. The mobility of electrons is 0.14 m2 V-1 s-1 and their number density is 1.5 × 1016 m-3. The electron current is (A) 6.72 × 10 -4 A (B) 6.72 × 10-5 A (C) 6.72 × 10-6 A (D) 6.72 × 10-7 A

Tardigrade Admin · Accepted Answer

As E = (V/l) = (2V/0.1 m) = 20 V m-1 A = 1.0 cm2 = 1.0 × 10-4m2 ve = μe E = 0.14 × 20 = 2.8 ms-1 The electron current is Ie = neAeve = (1.5× 1016)× (1.0× 10-4) × (1.6× 10-19)× 2.8 = 6.72× 10-7 A

Q. A block of pure silicon at $300 K$ has a length of $10 c m$ and an area of $1.0 c m^{2}$ . A battery of emf $2 V$ is connected across it. The mobility of electrons is $0.14 m^{2} V^{- 1} s^{- 1}$ and their number density is $1.5 \times 1 0^{16} m^{- 3}$ . The electron current is

$6.72 \times 1 0^{- 4} A$

$6.72 \times 1 0^{- 5} A$

$6.72 \times 1 0^{- 6} A$

$6.72 \times 1 0^{- 7} A$

Q. A block of pure silicon at 300K has a length of 10cm and an area of 1.0cm2. A battery of emf 2V is connected across it. The mobility of electrons is 0.14m2V−1s−1 and their number density is 1.5×1016m−3. The electron current is

6.72×10−4A

6.72×10−5A

6.72×10−6A

6.72×10−7A

As E=lV​=0.1m2V​ =20Vm−1 A=1.0cm2 =1.0×10−4m2 ve​=μe​E =0.14×20 =2.8ms−1 The electron current is Ie​=ne​Aeve​ =(1.5×1016)×(1.0×10−4)×(1.6×10−19)×2.8 =6.72×10−7A

Q. A block of pure silicon at $300 K$ has a length of $10 c m$ and an area of $1.0 c m^{2}$ . A battery of emf $2 V$ is connected across it. The mobility of electrons is $0.14 m^{2} V^{- 1} s^{- 1}$ and their number density is $1.5 \times 1 0^{16} m^{- 3}$ . The electron current is

$6.72 \times 1 0^{- 4} A$

$6.72 \times 1 0^{- 5} A$

$6.72 \times 1 0^{- 6} A$

$6.72 \times 1 0^{- 7} A$