A block of mass M placed inside a box descends vertically with acceleration 'a'. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of 'a' will be :

Question

A block of mass M placed inside a box descends vertically with acceleration 'a'. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of 'a' will be : (A) (g/4) (B) ( g /2) (C) (3 g /4) (D) g

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/afc449aaa1d47fc805c0c9d95758a861-.png" /> m g-N=m a a=g-(g/4) a=(3 g/4)

Q. A block of mass $M$ placed inside a box descends vertically with acceleration ' $a$ '. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of ' $a$ ' will be :

$\frac{g}{4}$

$\frac{g}{2}$

$\frac{3 g}{4}$

$g$

$m g - N = ma$
$a = g - \frac{g}{4}$
$a = \frac{3 g}{4}$

Q. A block of mass M placed inside a box descends vertically with acceleration 'a'. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of 'a' will be :

4g​

2g​

43g​

g

mg−N=ma a=g−4g​ a=43g​

Q. A block of mass $M$ placed inside a box descends vertically with acceleration ' $a$ '. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of ' $a$ ' will be :

$\frac{g}{4}$

$\frac{g}{2}$

$\frac{3 g}{4}$

$g$

$m g - N = ma$
$a = g - \frac{g}{4}$
$a = \frac{3 g}{4}$