A block of mass m moving with velocity v0 on a smooth horizontal surface hits the spring of constant k as shown. The maximum compression in spring is

Question

A block of mass m moving with velocity v0 on a smooth horizontal surface hits the spring of constant k as shown. The maximum compression in spring is (A) √(2 m/k) ⋅ v0 (B) √(m/k) ⋅ v0 (C) √(m/2 k) ⋅ v0 (D) (m/2 k) ⋅ v0

Tardigrade Admin · Accepted Answer

Ei=Ef (1/2) m v02=(1/2) k x2 x=√(m/k) v0

Q. A block of mass $m$ moving with velocity $v_{0}$ on a smooth horizontal surface hits the spring of constant $k$ as shown. The maximum compression in spring is

$\frac{2 m}{k} \cdot v_{0}$

$\frac{m}{k} \cdot v_{0}$

$\frac{m}{2 k} \cdot v_{0}$

$\frac{m}{2 k} \cdot v_{0}$

$E_{i} = E_{f}$
$\frac{1}{2} m v_{0}^{2} = \frac{1}{2} k x^{2}$
$x = \frac{m}{k} v_{0}$

Q. A block of mass m moving with velocity v0​ on a smooth horizontal surface hits the spring of constant k as shown. The maximum compression in spring is

k2m​​⋅v0​

km​​⋅v0​

2km​​⋅v0​

2km​⋅v0​

Ei​=Ef​ 21​mv02​=21​kx2 x=km​​v0​

Q. A block of mass $m$ moving with velocity $v_{0}$ on a smooth horizontal surface hits the spring of constant $k$ as shown. The maximum compression in spring is

$\frac{2 m}{k} \cdot v_{0}$

$\frac{m}{k} \cdot v_{0}$

$\frac{m}{2 k} \cdot v_{0}$

$\frac{m}{2 k} \cdot v_{0}$

$E_{i} = E_{f}$
$\frac{1}{2} m v_{0}^{2} = \frac{1}{2} k x^{2}$
$x = \frac{m}{k} v_{0}$