A block of mass m is pulled along a circular arc by means of a constant horizontal force F as shown. Work done by this force in pulling the block from A to B is

Question

A block of mass m is pulled along a circular arc by means of a constant horizontal force F as shown. Work done by this force in pulling the block from A to B is (A) (F R/2) (B) F R (C) (√3/2) F R (D) m g R

Tardigrade Admin · Accepted Answer

Work = Force × (Displacement in the direction of force) =F(R sin 60°)=(√3/2) F R

Q. A block of mass $m$ is pulled along a circular arc by means of a constant horizontal force $F$ as shown. Work done by this force in pulling the block from $A$ to $B$ is

$\frac{FR}{2}$

$FR$

$\frac{3}{2} FR$

$m g R$

Work = Force $\times$ (Displacement in the direction of force)
$= F (R sin 6 0^{\circ}) = \frac{3}{2} FR$

Q. A block of mass m is pulled along a circular arc by means of a constant horizontal force F as shown. Work done by this force in pulling the block from A to B is

2FR​

FR

23​​FR

mgR