Q.
A block of mass $m$ is pulled along a circular arc by means of a constant horizontal force $F$ as shown. Work done by this force in pulling the block from $A$ to $B$ is
Work, Energy and Power
Solution:
Work = Force $\times$ (Displacement in the direction of force)
$=F\left(R \sin 60^{\circ}\right)=\frac{\sqrt{3}}{2} F R$
