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Tardigrade
Question
Physics
A block of mass 5 kg is placed on a wedge having inclination of 37° with the horizontal. Coefficient of friction between block and wedge is 0.8. Then select the correct statement:
Q. A block of mass "
5
k
g
" is placed on a wedge having inclination of
3
7
∘
with the horizontal. Coefficient of friction between block and wedge is
0.8
. Then select the correct statement:
1616
169
Laws of Motion
Report Error
A
Friction force between block and the wedge is 32 N.
B
Friction force between block and the wedge is 30 N.
C
Contact force between block and wedge is 80 N.
D
Contact force between block and wedge is 40 N.
Solution:
f
m
a
x
=
μ
m
g
cos
θ
=
.8
×
5
×
10
×
5
4
=
32
as
f
m
a
x
>
m
g
sin
θ
hence
friction
=
m
g
sin
θ
=
5
×
10
×
5
3
=
30
Newton
and
N
=
m
g
cos
θ
=
40
N
⇒
Contact force
=
(
30
)
2
+
(
40
)
2
=
50
N