A block of mass 5 kg is (i) pushed in case (A) and (ii) pulled in case (B), by a force F = 20 N, making an angle of 30º with the horizontal, as shown in the figures. The coefficient of friction between the block and floor is μ = 0.2. The difference between the accelerations of the block, in case (B) and case (A) will be: (g = 10 ms-2)

Question

A block of mass 5 kg is (i) pushed in case (A) and (ii) pulled in case (B), by a force F = 20 N, making an angle of 30º with the horizontal, as shown in the figures. The coefficient of friction between the block and floor is μ = 0.2. The difference between the accelerations of the block, in case (B) and case (A) will be: (g = 10 ms-2) (A) 0 ms-2 (B) 0.8 ms-2 (C) 0.4 ms-2 (D) 3.2 ms-2

Tardigrade Admin · Accepted Answer

N1 = 60 N2 = 40 a1 = (10√3 - 0.2 × 60/5) a2 = (10√3 - 0.2 × 40/5) a1 - a2 = 0.8

$0 m s^{- 2}$

$0.8 m s^{- 2}$

$0.4 m s^{- 2}$

$3.2 m s^{- 2}$

$N_{1} = 60 N_{2} = 40$
$a_{1} = \frac{10 3 - 0.2 \times 60}{5} a_{2} = \frac{10 3 - 0.2 \times 40}{5}$
$a_{1} - a_{2} = 0.8$

0ms−2

0.8ms−2

0.4ms−2

3.2ms−2

N1​=60N2​=40 a1​=5103​−0.2×60​a2​=5103​−0.2×40​ a1​−a2​=0.8

$0 m s^{- 2}$

$0.8 m s^{- 2}$

$0.4 m s^{- 2}$

$3.2 m s^{- 2}$

$N_{1} = 60 N_{2} = 40$
$a_{1} = \frac{10 3 - 0.2 \times 60}{5} a_{2} = \frac{10 3 - 0.2 \times 40}{5}$
$a_{1} - a_{2} = 0.8$