A block of mass 2 kg is placed on the surface of a trolley of mass 20 kg which is on a smooth surface. The coefficient of friction between the block and the surface of the trolley is 0.25 . If a horizontal force of 2 N acts on the block, the acceleration of the system in ms-2 is (g=10 ms-2)

Question

A block of mass 2 kg is placed on the surface of a trolley of mass 20 kg which is on a smooth surface. The coefficient of friction between the block and the surface of the trolley is 0.25 . If a horizontal force of 2 N acts on the block, the acceleration of the system in ms-2 is (g=10 ms-2)  (A) 1.8 (B) 1.0 (C) 0.9 (D) 0.09

Tardigrade Admin · Accepted Answer

The force of limiting friction between the block and trolley

f_{1} = μ R = μ m g

0.25 \times 2 \times 10 = 5 N

Since,

F = 2 N, F < f_{L}

So, both will move together with acceieration

a_{B} = a_{T} = \frac{2}{20 + 2}

= \frac{1}{11} = 0.09 m s^{- 2}

Q. A block of mass 2kg is placed on the surface of a trolley of mass 20kg which is on a smooth surface. The coefficient of friction between the block and the surface of the trolley is 0.25 . If a horizontal force of 2N acts on the block, the acceleration of the system in ms−2 is (g=10ms−2)

1.8

1.0

0.9

0.09

The force of limiting friction between the block and trolley f1​=μR=μmg 0.25×2×10=5N Since, F=2N,F<fL​ So, both will move together with acceieration aB​=aT​=20+22​ =111​=0.09ms−2

The force of limiting friction between the block and trolley
$f_{1} = μ R = μ m g$
$0.25 \times 2 \times 10 = 5 N$

Since, $F = 2 N, F < f_{L}$
So, both will move together with acceieration
$a_{B} = a_{T} = \frac{2}{20 + 2}$
$= \frac{1}{11} = 0.09 m s^{- 2}$