A block of mass 2 kg slides down the face of a smooth 45° wedge of mass 9 kg as shown in figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge

Question

A block of mass 2 kg slides down the face of a smooth 45° wedge of mass 9 kg as shown in figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/9e6dcfb9d1709fcac8ebf7339530d57f-.png" /> (A) 2 m/s2 (B) (11/√2) m /s2 (C) 1 m/s2 (D) none of these

Tardigrade Admin · Accepted Answer

a is accelerate of block w.r.t. wedge <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/dc44055cdfa492a2b11182eef8e05011-.png" /> For block: N+mA sin 45° =mg cos 45° ldots(i) For wedge: N sin 45°=MA ldots(ii) From (i) and (ii) A = 1 m/s2

Q. A block of mass $2 k g$ slides down the face of a smooth $4 5^{\circ}$ wedge of mass $9 k g$ as shown in figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge

$2 m / s^{2}$

$\frac{11}{2} m / s^{2}$

$1 m / s^{2}$

none of these

$a$ is accelerate of block w.r.t. wedge

For block:

$N + m A s in 4 5^{\circ}$

$= m g cos 4 5^{\circ} \dots (i)$

For wedge: $N s in 4 5^{\circ} = M A \dots (ii)$

From (i) and (ii) $A = 1 m / s^{2}$

Q. A block of mass 2kg slides down the face of a smooth 45∘ wedge of mass 9kg as shown in figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge

2m/s2

2​11​m/s2

1m/s2