A block of mass 2 kg is dropped from a height of 40 cm on a spring whose force-constant is 1960 N m-1 . The maximum distance through which the spring is compressed by

Question

A block of mass 2 kg is dropped from a height of 40 cm on a spring whose force-constant is 1960 N m-1 . The maximum distance through which the spring is compressed by (A)  5 cm  (B)  15 cm  (C)  20 cm  (D)  10 cm

Tardigrade Admin · Accepted Answer

mg(h + x)= (1/2)kx2 Here, m = 2 kg , h = 40 cm k = 1960 N m-1 and g = 10 ms-2 . ∴ 2 ×10(0.40+x)= (1/2)×1960 x2 On solving, we get x = 10 cm .

Q. A block of mass $2 k g$ is dropped from a height of $40 c m$ on a spring whose force-constant is $1960 N m^{- 1}$ . The maximum distance through which the spring is compressed by

$5 c m$

$15 c m$

$20 c m$

$10 c m$

$m g (h + x) = \frac{1}{2} k x^{2}$
Here, $m = 2 k g$ , $h = 40 c m$
$k = 1960 N m^{- 1}$ and $g = 10 m s^{- 2}$ .
$∴ 2 \times 10 (0.40 + x) = \frac{1}{2} \times 1960 x^{2}$
On solving, we get $x = 10 c m$ .

Q. A block of mass 2kg is dropped from a height of 40cm on a spring whose force-constant is 1960Nm−1 . The maximum distance through which the spring is compressed by

5cm

15cm

20cm

10cm