Q.
A block of aluminium of mass 1kg and volume 3.6×10−4m3 is suspended from a string and then completely immersed in a container of water. The decrese in tension in a container of water. The decrease in tension in the string after immersion is
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Mechanical Properties of Fluids
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Solution:
Here, mass of block =m=1kg
Volume of the block, V=3.6×10−4m3
Tension in the string, T=mg=mg−Vρwater g ∴ Decrease in the tension of string T−T′=mg−[mg−vρwater g]=Vρwater g =3.6×10−4m3×103kgm−3×10ms−2=3.6N