A block of 10 kg mass is placed on a rough inclined surface as shown in figure. The acceleration of the block will be

Question

A block of 10 kg mass is placed on a rough inclined surface as shown in figure. The acceleration of the block will be (A) Zero (B) g (C) (g/2) (D) (√3 g/2)

Tardigrade Admin · Accepted Answer

FL=μs m g cos θ =(1)(100) (√3/2)=50 √3 Gravitational force =m g sin θ=50 N fL > m g sin θ ⇒ block will not move

Q. A block of $10 k g$ mass is placed on a rough inclined surface as shown in figure. The acceleration of the block will be

Zero

$g$

$\frac{g}{2}$

$\frac{3 g}{2}$

$F_{L} = μ_{s} m g cos θ$
$= (1) (100) \frac{3}{2} = 503$
Gravitational force $= m g sin θ = 50 N$
$f_{L} > m g sin θ$
$\Rightarrow$ block will not move

Q. A block of 10kg mass is placed on a rough inclined surface as shown in figure. The acceleration of the block will be

Zero

g

2g​

23​g​

FL​=μs​mgcosθ =(1)(100)23​​=503​ Gravitational force =mgsinθ=50N fL​>mgsinθ ⇒ block will not move

Q. A block of $10 k g$ mass is placed on a rough inclined surface as shown in figure. The acceleration of the block will be

$g$

$\frac{g}{2}$

$\frac{3 g}{2}$

$F_{L} = μ_{s} m g cos θ$
$= (1) (100) \frac{3}{2} = 503$
Gravitational force $= m g sin θ = 50 N$
$f_{L} > m g sin θ$
$\Rightarrow$ block will not move