Thank you for reporting, we will resolve it shortly
Q.
A block of $10\, kg$ mass is placed on a rough inclined surface as shown in figure. The acceleration of the block will be
Laws of Motion
Solution:
$F_{L}=\mu_{s} m g \cos \theta$
$=(1)(100) \frac{\sqrt{3}}{2}=50 \sqrt{3} $
Gravitational force $=m g \sin \theta=50\, N$
$f_{L} > m g \sin \theta$
$\Rightarrow $ block will not move
