A block (mass =M kg ) is placed on a rough inclined plane. A force F is applied parallel to the inclined (as shown in figure) such that it just starts moving upward. The value of F is

Question

A block (mass =M kg ) is placed on a rough inclined plane. A force F is applied parallel to the inclined (as shown in figure) such that it just starts moving upward. The value of F is (A) M g sin θ-μ M g cos θ (B) M g sin θ+μ M g cos θ) (C) M g sin θ (D) μ M g cos θ

Tardigrade Admin · Accepted Answer

F will oppose friction force and gravitation force F=m g sin θ+μ m g cos θ

Q. A block (mass $= M k g$ ) is placed on a rough inclined plane. A force $F$ is applied parallel to the inclined (as shown in figure) such that it just starts moving upward. The value of $F$ is

$M g sin θ - μ M g cos θ$

$M g sin θ + μ M g cos θ)$

$M g sin θ$

$μ M g cos θ$

$F$ will oppose friction force and gravitation force
$F = m g sin θ + μ m g cos θ$

Q. A block (mass =Mkg ) is placed on a rough inclined plane. A force F is applied parallel to the inclined (as shown in figure) such that it just starts moving upward. The value of F is

Mgsinθ−μMgcosθ

Mgsinθ+μMgcosθ)

Mgsinθ

μMgcosθ