A block is released from rest from a height h = 5 m. After travelling through the smooth curved surface it moves on the rough horizontal surface through a length l = 8 m and climbs onto the other smooth curved surface through a height h'. If μ=0.5,, find h'

Question

A block is released from rest from a height h = 5 m. After travelling through the smooth curved surface it moves on the rough horizontal surface through a length l = 8 m and climbs onto the other smooth curved surface through a height h'. If μ=0.5,, find h' <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7e3eb40343fce2c46d676522f2f0d977-.png" /> (A) 2 m (B) 3 m (C) 1 m (D) zero

Tardigrade Admin · Accepted Answer

The forces acting on the block and N, gravity and friction <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a51d398eb056e2ff423c554ace96bb4a-.png" /> Wf+Wf+W gr = DK Where WN=0, Wf=-μ mgl and W gr =m g(h-h') and Δ K=0 Thus, -μ m g l +m g(h-h')=0 h'=h-μ l=5-(1/2) × 8=1 m

Q. A block is released from rest from a height $h = 5 m .$ After travelling through the smooth curved surface it moves on the rough horizontal surface through a length $l = 8 m$ and climbs onto the other smooth curved surface through a height $h^{'}$ . If $μ = 0.5,$ , find $h^{'}$

2 m

3 m

1 m

zero

The forces acting on the block and $N$ , gravity and friction

$W_{f} + W_{f} + W_{g r} = DK$
Where $W_{N} = 0, W_{f} = - μ m g l$
and $W_{g r} = m g (h - h^{'})$
and $Δ K = 0$
Thus, $- μ m g l + m g (h - h^{'}) = 0$
$h^{'} = h - μ l = 5 - \frac{1}{2} \times 8 = 1 m$

Q. A block is released from rest from a height h=5m. After travelling through the smooth curved surface it moves on the rough horizontal surface through a length l=8m and climbs onto the other smooth curved surface through a height h′. If μ=0.5,, find h′

2 m

3 m

1 m

zero

The forces acting on the block and N, gravity and friction Wf​+Wf​+Wgr​=DK Where WN​=0,Wf​=−μmgl and Wgr​=mg(h−h′) and ΔK=0 Thus, −μmgl+mg(h−h′)=0 h′=h−μl=5−21​×8=1m

Q. A block is released from rest from a height $h = 5 m .$ After travelling through the smooth curved surface it moves on the rough horizontal surface through a length $l = 8 m$ and climbs onto the other smooth curved surface through a height $h^{'}$ . If $μ = 0.5,$ , find $h^{'}$

The forces acting on the block and $N$ , gravity and friction

$W_{f} + W_{f} + W_{g r} = DK$
Where $W_{N} = 0, W_{f} = - μ m g l$
and $W_{g r} = m g (h - h^{'})$
and $Δ K = 0$
Thus, $- μ m g l + m g (h - h^{'}) = 0$
$h^{'} = h - μ l = 5 - \frac{1}{2} \times 8 = 1 m$