Q.
A black rectangular surface of area A emits energy E per second at 27∘C . If length and breadth are reduced to 1/3rd of initial value and temperature is raised to 327∘C , then energy emitted per second becomes
2053
241
NTA AbhyasNTA Abhyas 2020Thermal Properties of Matter
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Solution:
E=eσ.A(T4−T04)andA=lb
When l and b changes to 3l and 3b A→9A EE′=AA′(27+273)4(327+273)4 ∴EE′=91(300600)4 ∴E′=91×(2)4×E E′=916E