Question

A black die and a white die are rolled. Find the probability that the number shown by the black die will be more than twice that shown by the white die.

• A. 1/8
• B. 1/6
• C. 1/3
• D. 1/4

Answer 1

Answer: (B)

The number of favourable cases are shown below:

1	3
1	4
1	5
1	6
2	5
2	6

There are $6$ favourable cases in which the number on black die is more than twice the number on the white die.
$\therefore m=6$
$n=$ Total number of cases $=6\times 6$
( $\therefore$ with each die there are six possibilities)
$\therefore$ Probability $p=\frac{m}{n}=\frac{6}{6\times 6}=\frac{1}{6}$