Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A black body radiates heat at temperatures ‘T1’ and ‘T2’ (T2 > T1). The frequency corresponding to maximum energy is
Q. A black body radiates heat at temperatures ‘
T
1
’ and ‘
T
2
’
(
T
2
>
T
1
)
. The frequency corresponding to maximum energy is
1962
208
MHT CET
MHT CET 2015
Report Error
A
more at
T
1
B
more at
T
2
C
equal for
T
1
and
T
2
D
independent of
T
1
and
T
2
Solution:
Energy radiated by the bodies are
E
1
=
σ
A
T
1
4
and
E
2
=
σ
A
T
2
4
⇒
E
1
E
2
=
(
T
1
T
2
)
4
>
1
[
∵
T
2
>
T
1
]
⇒
E
2
>
E
1
or
h
v
2
>
h
v
1
or
v
2
>
v
2
Thus, frequency corresponding to
T
2
is more.