A black body has maximum energy at wavelength λ m at temperature 2000 K. The corresponding wavelength at a temperature of 3000 K will be

Question

A black body has maximum energy at wavelength λ m at temperature 2000 K. The corresponding wavelength at a temperature of 3000 K will be (A)  (3/2)λ m  (B)  (2/3)λ m  (C)  (4/9)λ m  (D)  (9/4)λ m

Tardigrade Admin · Accepted Answer

From Wiens law 2000× λ m=3000× λ m λ m=(2/3)λ m

Q. A black body has maximum energy at wavelength $λ_{m}$ at temperature 2000 K. The corresponding wavelength at a temperature of 3000 K will be

$\frac{3}{2} λ_{m}$

$\frac{2}{3} λ_{m}$

$\frac{4}{9} λ_{m}$

$\frac{9}{4} λ_{m}$

From Wiens law
$2000 \times λ_{m} = 3000 \times λ_{m}$
$λ_{m} = \frac{2}{3} λ_{m}$

Q. A black body has maximum energy at wavelength λm​ at temperature 2000 K. The corresponding wavelength at a temperature of 3000 K will be

23​λm​

32​λm​

94​λm​

49​λm​