Question

A bivalent metal has an equivalent mass of $32$. The molecular mass of the metal nitrate is

• A. 192
• B. 188
• C. 182
• D. 168

Answer 1

Answer: (B)

Atomic mass of the metal $=32\times 2=64$
Formula of metal nitrate $=M{\left(N{O}_3\right)}_2$
$\therefore$ Molecular mass $=64+28+96=188$