A binary mixture of bivalent metals having mass 2 g molecular mass of A and B are 15 and 30 respectively, is dissolved in HCl, it evolve 2.24 L H 2 at STP, what is the mass of A present in mixture?

Question

A binary mixture of bivalent metals having mass 2 g molecular mass of A and B are 15 and 30 respectively, is dissolved in HCl, it evolve 2.24 L H 2 at STP, what is the mass of A present in mixture? (A) 1 g (B) 1.5 g (C) 0.5 g (D) 0.75 g

Tardigrade Admin · Accepted Answer

A +2 HCl arrow ACl 2+ H 2 mole =(x/15) (x/15) B +2 HCl arrow BCl 2+ H 2 mole =(2-x/30) (2-x/30) Mole of H 2=(x/15)+(2-x/30)=(2.24/22.4)=(1/10) (x/15)-(x/30)=(1/10)-(1/15) x=1 g

Q. A binary mixture of bivalent metals having mass $2 g$ molecular mass of $A$ and $B$ are $15$ and $30$ respectively, is dissolved in $H Cl$ , it evolve $2.24 L H_{2}$ at STP, what is the mass of A present in mixture?

$1 g$

$1.5 g$

$0.5 g$

$0.75 g$

Q. A binary mixture of bivalent metals having mass 2g molecular mass of A and B are 15 and 30 respectively, is dissolved in HCl, it evolve 2.24LH2​ at STP, what is the mass of A present in mixture?

1g

1.5g

0.5g

0.75g

A+2HCl→ACl2​+H2​ mole =15x​15x​ B+2HCl→BCl2​+H2​ mole =302−x​302−x​ Mole of H2​=15x​+302−x​=22.42.24​=101​ 15x​−30x​=101​−151​ x=1g

Q. A binary mixture of bivalent metals having mass $2 g$ molecular mass of $A$ and $B$ are $15$ and $30$ respectively, is dissolved in $H Cl$ , it evolve $2.24 L H_{2}$ at STP, what is the mass of A present in mixture?

$1 g$

$1.5 g$

$0.5 g$

$0.75 g$