A big circular coil of 1000 turns and average radius 10 m is rotating about its horizontal diameter at 2 rad s -1. If the vertical component of earth's magnetic field at that place is 2 × 10-5 T and electrical resistance of the coil is 12.56 Ω, then the maximum induced current in the coil will be:

Question

A big circular coil of 1000 turns and average radius 10 m is rotating about its horizontal diameter at 2 rad s -1. If the vertical component of earth's magnetic field at that place is 2 × 10-5 T and electrical resistance of the coil is 12.56 Ω, then the maximum induced current in the coil will be: (A) 2 A (B) 0.25 A (C) 1.5 A (D) 1 A

Tardigrade Admin · Accepted Answer

i max =( E max / R )=( NBA ω / R ) i max =(1000 × 2 × 10-5 × π(102) × 2/12.56) i max =1 A

$2 A$

$0.25 A$

$1.5 A$

$1 A$

$i_{m a x} = \frac{E _{m a x}}{R} = \frac{NB A ω}{R}$
$i_{m a x} = \frac{1000 \times 2 \times 1 0 ^{- 5} \times π ( 1 0 ^{2} ) \times 2}{12.56}$
$i_{m a x} = 1 A$

Q. A big circular coil of 1000 turns and average radius 10m is rotating about its horizontal diameter at 2rads−1. If the vertical component of earth's magnetic field at that place is 2×10−5T and electrical resistance of the coil is 12.56Ω, then the maximum induced current in the coil will be:

2A

0.25A

1.5A

1A

imax​=REmax​​=RNBAω​ imax​=12.561000×2×10−5×π(102)×2​ imax​=1A

$2 A$

$0.25 A$

$1.5 A$

$1 A$

$i_{m a x} = \frac{E _{m a x}}{R} = \frac{NB A ω}{R}$
$i_{m a x} = \frac{1000 \times 2 \times 1 0 ^{- 5} \times π ( 1 0 ^{2} ) \times 2}{12.56}$
$i_{m a x} = 1 A$