A beam of metal supported at the two edges is loaded at the centre. The depression at the centre is proportional to

Question

A beam of metal supported at the two edges is loaded at the centre. The depression at the centre is proportional to (A) Y 2 (B) Y (C) 1 / Y (D) 1 / Y 2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/45b5ccdff5a420b339087d028301caf5-.png" /> For a beam, the depression at the centre is given by, δ=((f L/4 Y b d3)) [f, L, b, d are constants for a particular beam] i.e., δ propto (1/Y)

Q. A beam of metal supported at the two edges is loaded at the centre. The depression at the centre is proportional to

$Y^{2}$

$Y$

$1/ Y$

$1/ Y^{2}$

For a beam, the depression at the centre is given by, $δ = (\frac{f L}{4 Yb d ^{3}})$
[ $f, L, b, d$ are constants for a particular beam] i.e., $δ \propto \frac{1}{Y}$

Q. A beam of metal supported at the two edges is loaded at the centre. The depression at the centre is proportional to

Y2

Y

1/Y

1/Y2

For a beam, the depression at the centre is given by, δ=(4Ybd3fL​) [f,L,b,d are constants for a particular beam] i.e., δ∝Y1​

$Y^{2}$

$Y$

$1/ Y$

$1/ Y^{2}$

For a beam, the depression at the centre is given by, $δ = (\frac{f L}{4 Yb d ^{3}})$
[ $f, L, b, d$ are constants for a particular beam] i.e., $δ \propto \frac{1}{Y}$