A beaker full of hot water is kept in a room. If it cools from 80°C to 75°C in t1 , minutes, from 75°C to 70°C in t 2 minutes and from 70°C to 65°C in t3 minutes, then

Question

A beaker full of hot water is kept in a room. If it cools from 80°C to 75°C in t1 , minutes, from 75°C to 70°C in t 2 minutes and from 70°C to 65°C in t3 minutes, then (A) t1< t2 < t3 (B) t1> t2 > t3 (C) t1= t2 = t3 (D) t1< t2 = t3

Tardigrade Admin · Accepted Answer

: The rate of cooling is directly proportional to the temperature difference of the body and the surroundings. So, cooling will be fastest in the first case and slowest in the third case.

Q. A beaker full of hot water is kept in a room. If it cools from 80 $^{\circ}$ C to 75 $^{\circ}$ C in $t_{1}$ , minutes, from 75 $^{\circ}$ C to 70 $^{\circ}$ C in $t_{2}$ minutes and from 70 $^{\circ}$ C to 65 $^{\circ}$ C in $t_{3}$ minutes, then

$t_{1} < t_{2} < t_{3}$

$t_{1} > t_{2} > t_{3}$

$t_{1} = t_{2} = t_{3}$

$t_{1} < t_{2} = t_{3}$

: The rate of cooling is directly proportional to the temperature difference of the body and the surroundings. So, cooling will be fastest in the first case and slowest in the third case.

Q. A beaker full of hot water is kept in a room. If it cools from 80∘C to 75∘C in t1​, minutes, from 75∘C to 70∘C in t2​ minutes and from 70∘C to 65∘C in t3​ minutes, then

t1​<t2​<t3​

t1​>t2​>t3​

t1​=t2​=t3​

t1​<t2​=t3​

: The rate of cooling is directly proportional to the temperature difference of the body and the surroundings. So, cooling will be fastest in the first case and slowest in the third case.

Q. A beaker full of hot water is kept in a room. If it cools from 80 $^{\circ}$ C to 75 $^{\circ}$ C in $t_{1}$ , minutes, from 75 $^{\circ}$ C to 70 $^{\circ}$ C in $t_{2}$ minutes and from 70 $^{\circ}$ C to 65 $^{\circ}$ C in $t_{3}$ minutes, then

$t_{1} < t_{2} < t_{3}$

$t_{1} > t_{2} > t_{3}$

$t_{1} = t_{2} = t_{3}$

$t_{1} < t_{2} = t_{3}$