A battery of internal resistance 4 Ω is connected to the network of resistances as shown in figure. In order that the maximum power can be delivered to the network, the value of R should be

Question

A battery of internal resistance 4 Ω is connected to the network of resistances as shown in figure. In order that the maximum power can be delivered to the network, the value of R should be <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-yg6fqlvah37ak0vn.jpg" /> (A) (4/9) Ω (B) (8/3)Ω (C) 18Ω (D) 2Ω

Tardigrade Admin · Accepted Answer

The given circuit is a balanced Wheatstone's bridge. Solution

Thus, no current will flow across 6R of the side CD. The given circuit will now be equivalent to Solution

For maximum power, net external resistance = Total internal resistance or 2R=4 or R=2 Ω .

Q. A battery of internal resistance $4 Ω$ is connected to the network of resistances as shown in figure. In order that the maximum power can be delivered to the network, the value of $R$ should be

$\frac{4}{9}$ $Ω$

$\frac{8}{3} Ω$

$18Ω$

$2Ω$

The given circuit is a balanced Wheatstone's bridge.

Thus, no current will flow across $6 R$ of the side CD. The given circuit will now be equivalent to

For maximum power, net external resistance
= Total internal resistance
or $2 R = 4$
or $R = 2 Ω.$

Q. A battery of internal resistance 4Ω is connected to the network of resistances as shown in figure. In order that the maximum power can be delivered to the network, the value of R should be

94​ Ω

38​Ω

18Ω

2Ω