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Tardigrade
Question
Physics
A battery of emf, 10 V is connected to resistances as shown in figure. The potential difference VA-VB between the points A and B is
Q. A battery of emf,
10
V
is connected to resistances as shown in figure. The potential difference
V
A
−
V
B
between the points
A
and
B
is
1645
166
Current Electricity
Report Error
A
-2 V
7%
B
(
11
20
)
V
10%
C
2 V
70%
D
5 V
13%
Solution:
Total resistance of circuit
=
3
+
4
+
4
4
×
4
=
3
+
2
=
5
Ω
Current in circuit,
I
=
5
Ω
10
V
=
2
A
Current through arm
C
A
D
or
CB
D
=
1
A
Thus
V
C
−
V
A
=
1
×
1
=
1
V
and
V
C
−
V
B
=
1
×
3
=
3
V
Hence
V
A
−
V
B
=
(
V
C
−
V
B
)
−
V
C
−
V
A
)
=
3
−
1
=
2
V