A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. The current in the circuit is 0.5 A, The terminal voltage of the battery when the circuit is closed is

Question

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. The current in the circuit is 0.5 A, The terminal voltage of the battery when the circuit is closed is (A) 10 V (B) 0 V (C) 1.5V (D) 8.5V

Tardigrade Admin · Accepted Answer

Terminal voltage of the battery after closing the circuit is V=E-ir =10-0.5× 3 =10-1.5 =8.5V

Q. A battery of emf 10 V and internal resistance $3 Ω$ is connected to a resistor. The current in the circuit is 0.5 A, The terminal voltage of the battery when the circuit is closed is

10 V

0 V

1.5V

8.5V

Terminal voltage of the battery after closing the circuit is $V = E - i r$ $= 10 - 0.5 \times 3$ $= 10 - 1.5$ $= 8.5 V$

Q. A battery of emf 10 V and internal resistance 3Ω is connected to a resistor. The current in the circuit is 0.5 A, The terminal voltage of the battery when the circuit is closed is

10 V

0 V

1.5V

8.5V

Terminal voltage of the battery after closing the circuit is V=E−ir =10−0.5×3 =10−1.5 =8.5V

Q. A battery of emf 10 V and internal resistance $3 Ω$ is connected to a resistor. The current in the circuit is 0.5 A, The terminal voltage of the battery when the circuit is closed is

Terminal voltage of the battery after closing the circuit is $V = E - i r$ $= 10 - 0.5 \times 3$ $= 10 - 1.5$ $= 8.5 V$