A battery is charged at a potential of 15 V for 8 hours when the current flowing is 10 A. The battery on discharge supplies a current of 5 A for 15 hours. The mean terminal voltage during discharges is 14 V. The "Watt hour" efficiency of the battery is :-

Question

A battery is charged at a potential of 15 V for 8 hours when the current flowing is 10 A. The battery on discharge supplies a current of 5 A for 15 hours. The mean terminal voltage during discharges is 14 V. The "Watt hour" efficiency of the battery is :- (A) 80 % (B) 90 % (C) 87.5 % (D) 82.5 %

Tardigrade Admin · Accepted Answer

% Watt hour efficiency = (Eout/Ein) × 100 = ((14)(5)(15)/(15)(10)(8)) × = 87.5%

Q. A battery is charged at a potential of $15 V$ for $8$ hours when the current flowing is $10 A$ . The battery on discharge supplies a current of $5 A$ for $15$ hours. The mean terminal voltage during discharges is $14 V$ . The "Watt hour" efficiency of the battery is :-

80 %

90 %

87.5 %

82.5 %

% Watt hour efficiency = $\frac{E _{o u t}}{E _{in}} \times 100$
= $\frac{( 14 ) ( 5 ) ( 15 )}{( 15 ) ( 10 ) ( 8 )} \times = 87.5$ %

Q. A battery is charged at a potential of 15V for 8 hours when the current flowing is 10A. The battery on discharge supplies a current of 5A for 15 hours. The mean terminal voltage during discharges is 14V. The "Watt hour" efficiency of the battery is :-