A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current (I) in the circuit verses the number of cells will be as shown in figure.

Question

A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current (I) in the circuit verses the number of cells will be as shown in figure. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

I =( n ε/ nr )=(ε/ r ) So, I is independent of n and I is constant. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5abe38874f33960eecf7d7031949c765-.png" />

Q. A battery consists of a variable number $(n)$ of identical cells, each having an internal resistance $r$ connected in series. The terminals of the battery are short-circuited. A graph of current $(I)$ in the circuit verses the number of cells will be as shown in figure.

$I = \frac{n ε}{n r} = \frac{ε}{r}$
So, $I$ is independent of $n$ and $I$ is constant.

Q. A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current (I) in the circuit verses the number of cells will be as shown in figure.

I=nrnε​=rε​ So, I is independent of n and I is constant.

Q. A battery consists of a variable number $(n)$ of identical cells, each having an internal resistance $r$ connected in series. The terminals of the battery are short-circuited. A graph of current $(I)$ in the circuit verses the number of cells will be as shown in figure.

$I = \frac{n ε}{n r} = \frac{ε}{r}$
So, $I$ is independent of $n$ and $I$ is constant.